![]() ![]() Remember, a pull is just a fetch then merge from a remote repo to your local repo on whatever branch you are currently focused on. So go ahead and update the local master with the remote master's updates first using a pull, then try your xyz branch pull again. The local repo user has no way to merge that change as its master branch is missing those new added commits at the end, so cannot update the xyz rebase change until its local master branch on its repo is updated with a merge via a pull, first. These could be new commits or changes the other developer added to the remote master branch, who then ran a rebase on their xyz branch to move it to the end of those new commit HEADS in the remote master. The fast-forward message likely means that the xyz branch on the remote repo cannot update the local repo's xyz branch until the local repo gets all the changes added to its master branch from the remote repo first. local repository, synchronizing 104, 105 remote repository 103 specific branch 103, 104 forked repository G pull request, creating from 149 Git 6. It sounds like the master branch on the remote repository has been changed with new commits the local repository does not have. If this is failing, it has nothing to do with the two xyz branches on remote and local repositories not being able to merge. Simple! git checkout xyzīut, the user got an error! That update did not work. If you want to merge a remote xyz branch into a local xyz branch, where both branches exist off a master branch in a remote and local repository, just select or "checkout" the local xyz branch first, then do a "pull" on the same remote branch. The answer to Push branches to Git gives me the error "! " Merge it into an existing branch xyz in my local repo? How do I pull the branch xyz from the remote server (e.g. Or, to checkout a tag from a different remote use: git fetch yourremote -tags. None of these posts answers the original question! 1 - Fetch the tag from the remote with: git fetch origin -tags. The Local User Needs to Update Both the Master Branch and the XYZ Branches Separately Then merge it into your current branch (I'll assume that's master), and fix any merge conflicts: $ git merge origin/other-branch To solve your problem, first fetch the remote branch: $ git fetch origin other-branch However, this would not be a fast-forward merge: v master For example, if you have this history tree, then merging other-branch would result in a fast-forward merge: O-O-O-O-O-O A fast-forward merge is a merge in which the head of the branch you are trying to merge into is a direct descendent of the head of the branch you want to merge. However, when pull-ing, Git will only merge other-branch if it can perform a fast-forward merge. That is, a pull is just a fetch followed by a merge. Git is basically doing this: $ git fetch origin other-branch & git merge other-branch When you do this: $ git pull origin other-branch Let's say you've checked out branch master, and you want to merge in the remote branch other-branch. That's because Git can't merge the changes from the branches into your current master. But I get an error "! " and something about "non fast forward" ![]()
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